Standard Form



A number is said to be in standard form if it is re-written as a figure between 1 and 10 and then multiplied by a power of ten without changing its original value. i.e. P × 10x.

Note
When expressing numbers in standard form, point are either carried from the left hand side (LHS) or right hand side (RHS) of it. While the point carried from the left hand side turns negative the point from right hand side turns positive.

Another very important thing to note is that when expressing either decimal number or whole number in standard form, points are carried until they are between the 1st and 2nd value.

Example 1; Express 263,000,000 in standard form.

Solution
The value above is a whole number so you carry point (imaginary) from (RHS) towards (LHS). Let’s do it!







= 2.63 × 108. Answer


Example 2; Express 0.0006927 in standard form.

Solution
The value above is a decimal number so points are carried from the left hand side (LHS) – (RHS).

= 6.927 × 10-4.

Example 3; Express 34.694 in standard form.

Solution
Even though the value above is also a decimal number, points here will be carried from (RHS) – (LHS).

The result will be; 3.4694 × 101.

Ordinary Form
Ordinary form is the opposite of standard form. When you are expressing numbers in ordinary form it means going the other way round to get your answer.

For example; Express 3.4694 × 101 in ordinary form.

Solution
You are going to carry the point once from (LHS) – (RHS). Why? Because 10 is raised to power of 1.

3.4694 × 101

= 34.694. (Answer)

Practice these questions below;

1. Express the following in standard form;
(a) 54000
(b) 0.0003164
(c) 263.478
(d) 0.00000364
(e) 600.84

2. Find the value of A if 0.000046 = A × 10-5

3. What is the value of n if 0.0000094 = 9.4 × 10n?

4. Express the following in ordinary form;
(a) 2.83 × 108
(b) 4.765 × 10-3
(c) 1.278 × 102
(d) 9.87 × 10-9

Approximations



Approximations are linked to terms such as decimal places, significant figures, standard form and so on. It is a method of assuming precise values to figures. It is also a method of counting to the nearest whole numbers.

Common terms used in Approximations are decimal places (d.p) and significant figures (sigfig) or (s.f).

Note;
Before you can approximate any number, the following rule must be fully understood;
0
0
1
0
2
0
3
0
4
0
5
1
6
1
7
1
8
1
9
1

The table above simply suggest that during approximation, figures from 0-4 becomes 0 while figures from 5-9 becomes 1. Without knowing this rule it will be difficult for you to approximate any number.

Example 1; Correct 0.00630427 to 7 decimal places.

Solution
To do this, follow these steps;

Count 7 numbers after the decimal point. The seventh figure is ‘2’ and beside it is ‘7’ which falls between 5-9 so it becomes ‘1’ according to the rule in the table above. Add this ‘1’ to the seventh figure which is ‘2’, that gives 3.

The result is; 0.0063043. (Answer)

Example 2; Correct 15.300649 to 3 decimal places.

Solution

Count 3 numbers after the decimal point. The third number is ‘0’ and beside it is ‘6’ which falls between 5-9 so it becomes ‘1’ according to the rule above. Add this ‘1’ to the third number which is ‘0’, that gives 1.

The result is; 15.301000. This can also be written as 15.301. (Answer)

Note
All other numbers are rounded down and will become zero. It’s a rule!

Example 3; Express 0.006457 to 3 significant figures.

Solution
Applying the rule to significant figures is just a little bit different because here zeros are not counted unlike decimal places. In order to do this, follow the steps below;

Count 3 “non-zero” figures after the decimal point. The third figure is ‘5’ and beside it is ‘7’ which falls between 5-9 so it becomes ‘1’. Add this ‘1’ to the third figure which is ‘5’, that gives 6.

The result is; 0.00646. (Answer)

Example 4; Express 2.00584 to 4 sigfig.

Solution
A very important thing to note here is zeros that are found in between non-zero significant figures are counted as being significant.

Count 4 significant figures from the beginning of the number. The fourth figure will be ‘5’ and beside it is ‘8’ which falls between 5-9 so it becomes ‘1’. Add this ‘1’ to the fourth figure which is ‘5’, that gives 6.

The answer is 2.006.

Example 5; Round off 241.863 to the nearest whole number.

Solution
This is a little different from decimal places and significant figures but the same rule applies here as well.

To the nearest whole number means no decimal point should be found in the answer. This is how you do it;

Consider the figure after decimal point, which is ‘8’ and falls between 5-9 so it becomes ‘1’. Add this ‘1’ to the last figure before decimal point which is also 1 (1+1) that gives 2.

Therefore, the result is 242.

Example 6; Round off 2.2 hours to the nearest hours.

Solution
Follow the same step in example 5;

Consider the figure after decimal point which is ‘2’ and falls between 0-4 so it becomes ‘0’ according to the rule. Add this ‘0’ to the last figure before the decimal point which is 2 (0+2) that gives 2.

Answer is 2 hours.

Example 7; Take 173.245 to the nearest hundred.

Solution
In order to do this, you must follow place value counting system;

H T U
173.245
H stands for hundred
T stands for tens
U stands for units.

To the nearest hundred means; Consider the hundredth value which is ‘1’ beside it is ‘7’ which falls between 5-9 so it becomes ‘1’. Add this ‘1’ to the hundredth value which is also 1 (1+1), that gives 2.

The answer is 200. (Remember all the other values becomes zero)

Example 8; Express 92,681 in the nearest thousand.

Solution
Apply place value counting system;

TTH TH H T U
 92,681

To the nearest thousand means; Consider the thousandth value which is ‘2’ beside it is ‘6’ which falls between 5-9 so it becomes ‘1’. Add this ‘1’ to the thousandth value (2+1) that gives 3.

93,000. (Answer)

Practice these questions below;

1. Correct the following figures to the number of decimal places indicated.
(a) 3.0561 (2d.p)
(b) 0.008153 (1d.p)
(c) 0.09634 (3d.p)
(d) 0.0006005 (4d.p)

FRACTIONS


A fraction is part of a whole number which contains a numerator and denominator. A numerator is the figure placed on top while the denominator is the figure placed below. There are three types of fractions which are;

1. Proper Fraction; This is a fraction which has its numerator lower than the denominator E.g. ½, 2/5, 7/9, etc.

2. Improper Fraction; This has its numerator higher (bigger) than the denominator. E.g.  3/2, 4/3, 9/5, etc.

3. Mixed Fractions; This consists of a whole number and a proper fraction written together. E.g. 11/2, 23/4, 56/7, etc.

Solving any question related to fractions shouldn’t be difficult if students can master the term BODMAS. BODMAS stands for the order which arithmetic are carried out, which are as follows;

B; Bracket
O; Of
D; Division
M; Multiplication
A; Addition
S; Subtraction

Example 1; Simplify 52/3 ÷ (232/5 of 31/4 – 22)

Note;
Before applying the BODMAS rule to this question, you will have to convert all the mixed fractions to proper fractions. You can do these by multiplying the whole number with first the denominator and second add the result with the numerator and finally dividing your total result with the denominator. (This is the format of conversion; Whole Number × Denominator + Numerator ÷ Denominator).

= 17/3 ÷ (117/5 of 13/4 – 22)

Applying the rule means you’ll first deal with the ones in bracket where “of” stands for multiplication.
= 17/3 ÷ (117/5 × 13/4 – 22)
= 17/3 ÷ (1521/20 – 22)

Find the L.C.M of the fractions in bracket;
= 17/3 ÷ (1521/20440/20)

= 17/3 ÷ (1081/20)

Remove the bracket;
= 17/3 ÷ 1081/20

Note;
It is impossible to divide two fractions, so you’ll have to change the mathematical sign to multiplication (It’s a rule in mathematics) which makes the fraction to the right take an inverse form.

= 17/3 × 20/1081

= 340/3243 (Answer).

Example 2; Evaluate








Convert all mixed fractions to proper fractions;
 

 




Find the L.C.M of both fractions above and below;





 




= 11/4 ÷ 11/8 (Change division sign to multiplication sign just like example 1 above)

= 11/4 × 8/11 (11 cancels 11 while 4 in 8 gives 2)

= 2 (Answer).


Practice these questions below;

Simplify the following;

1. (a) 23/4 + 32/5 – 11/2
    (b) 21/6 + (33/5 ÷ 11/8)
    (c) (25/6 – 31/2) ÷ 11/2 of 52/3


2. Simplify this fraction; 






3. (a) 5/9 ÷ (13/81/3)
    (b)  51/3 ÷ (45/6 – 31/5)
    (c) 21/2 ÷ (21/4 ÷ 41/3)
 
4. Simplify this fraction below;