Showing posts with label Substitution in Algebra Fractions. Show all posts
Showing posts with label Substitution in Algebra Fractions. Show all posts

Substitution in Algebra Fractions


This type of Algebra fraction involves replacing one value for another. It might be an alphabet or a number.

Examples;

1. Given that x : y = 9 : 4, evaluate







Solution
Step 1

Note; The question above simply means that if x = 9 and y = 4 substitute for x and y in;
















Step 2
Cancellation Process; 4 cancels each other;










Step 3
Cancellation Process; 6 goes in 60 gives 10;

10.






Note; This question simply means that if x =
, substitute for x in
.
Don’t bother yourself about the word “express” it was just used to twist the question and make it more technical.





For further explanation, it means anywhere you see x in 
, you put the whole of 
. Ok, let’s do this!





Step 1






Step 2

NUMERATOR;

Remove the bracket;










Step 3
Find the L.C.M which is 3a – 2;





Step 4
Collect like terms;










Step 5

DENOMINATOR;

Expand by using 2 to multiply all the values in the bracket;













Step 6
Find L.C.M which is 6a – 4;





Step 7
Collect like terms;










Step 8
Combine Numerator and Denominator together;






Step 9
Expand;





Remember the rule which says that when dividing two algebra fractions sign must change to multiplication and the fraction to the right becomes inverse;





Step 10
Note; 6a – 4 and 10a + 2 are two digit values, so we look for their common factors;
NUMERATOR;
6a – 4  ---the common factor will be 2;
2(3a – 2)

Step 11
DENOMINATOR;
10a + 2  ---the common factor will be 2;
2(5a + 1)

Step 12
Combine all of them together;





Step 13
Cancellation Process; 3a – 2 cancels each other and 2 cancels 2;







Step 1
This question similar to example 1 above, so we follow the same process;
This means that x = 3 and y = 4.















Step 2
Cancellation Process; 2 goes in 2 gives 1 while 2 goes in 10 gives 5;










Step 1
Note; This question is similar to example 2 above, so we will follow the same process;
This means that you are to replace x with
;












Step 2

NUMERATOR;

Remove the bracket;










Step 3
Find L.C.M which is 3m + 5;





Step 4
Collect like terms;





Note; 3m – 3m equals 0 and – 5 + 5 also equals o;

 



Note; 0 divided by any value must give 0 as the answer, it’s a rule!;

0

Step 5

DENOMINATOR;

Remove the bracket;










Step 6
Find L.C.M which is 3m + 5;






Step 7
Collect like terms;










Step 8
Combine Numerator and Denominator together;





Step 9
Expand;





Step 10
Change sign to multiplication;





Note; 0 multiplied by any value must give 0 as the answer;

0.






Step 1
Simply put, replace P with 9 and q with 5 in
.






















Step 2
Cancellation Process; 125 goes in 125 to give 1;

1