Change of Subject Formula

Whenever the subject of a formula is to be changed, the intention is to make the value becoming the subject stand alone and remain on the left hand side of the expression. The methods used to effect this change may be any basic mathematical principles like multiplication, addition, subtraction, division, finding square roots, etc.

Whatever operation that is used to perform the change must be applied to both sides of the expression (formula).

Examples;
1. Make u the subject of the formula; v2 = u2 + 2as.





Solution

Step 1

Rearrange by bringing “u2” to the LHS of the expression and carrying v2 to the RHS of the expression. The reason for this is because you have been instructed to make “u” the subject of the formula according to the question.

-u2 = 2as – v2

Note;
Whenever you carry figures from one side of an expression to another, the sign changes to the opposite.

Step 2

Multiply both sides by -1 in order to eliminate the – (minus sign);

u2 = 2as + v2

Step 3

Take square root of both sides;





2. Change the subject of the formula below to h;

Solution

Step 1

The target value here is “h”. So in order to make “h” subject, you need to remove the square root by taking square of both sides;






Step 2

Cross multiply both sides;





2Qh = 100p2

Step 3

Divide both sides by 2Q;







Final answer will be;

3. Express S in terms of T, X and K in the formula below;




Solution

Step 1

Remove the square root by taking square of both sides;









Step 2

Split the RHS expression apart to make it easier for you to solve. See below;







Step 3

Expand (2X) ² and remove the square root;





Note; raise to power of 2 can easily cancel square root. This is why: (2 × ½ gives 1 where ½ is the mathematical interpretation of square root)









Step 4

Cross multiply both sides;
4SX² X 1 = T² X K
4SX² = KT²

Step 5

Divide both sides by 4X² because you need “S” to be alone;












Lastly, we need to find S when T = 8, X = 2 and K = 3. The only way to do this is by substituting for T, X and K respectively in our new formula.



















S = 3 × 4
Note; 16 goes in 64 gives 4
S = 12. (Answer)

Practice these questions below;

1. Make d the subject of the formula below; 








2. Make m the subject of the expression below;








3. Make v the subject of the relation;







4. Given that v2 = u2 + 2as, express a in terms of u, v and s. Hence, find the value of a when u = 15, v = 20 and s = 5.

5. An expression is given as

Make R the subject of the formula and find R when K = 20, q = 15 and D = 6.

67 comments:

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    ReplyDelete
  2. Replies
    1. I need a solution to this formula V=#h(h+r).make h the subject of the formula

      Delete
    2. Make m the subject of the relation h=mt/d(m+p)

      Delete
    3. dh=mt/m+p
      dhm + dhp =mt
      dhp= mt - dhm
      dhp = m(t-dh)
      m= dhp/t-dh

      Delete
  3. I wish you all the best. Useful post

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  4. The method is so simple for anyone to understand, keep this up.

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  5. This was copied from comprehensive mathematics new edition.

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    Replies
    1. please who is the author ofcomprehensive mathematics ?

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  6. Isn't no 1 supposed to be -2as because you multiplied both sides by -1 so isn't it meant to affect that?

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  7. How is this solved..
    E=v + 1/2mv^2

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  8. Please check the first example for me , I'm not understanding it

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  10. v2 = u2 + 2as
    Subtract 2as from both sides

    V2-2as=u2

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  18. If k=2(h+g) make h the subject of formula

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  19. If k=2(h+g) make h the subject of formula

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  22. H=M(v2-u2)/2gx make v subject of formula
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    1. V = +/- square root of [H2gx + MU^2/M]

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    2. I can't solve this I triedy best but it didn't work

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  23. x+y=2p make x the subject of formula
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  24. Please can you help me make R the subject of the formular in
    A=pieR [square root of H^2 —R^2]. With the working please

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  26. solve this p=aw+b the subject of formula is w

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  27. there is correction in example 1 when you multiply both sides by -1 the equation becomes u^2=v^2-2as

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  29. Pls can you solve this question; make h the subject of the formula in this question; √mh^2-16=h

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  32. Please make p the subject of formula in p=nrt\v

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