Substitution in Algebra Fractions


This type of Algebra fraction involves replacing one value for another. It might be an alphabet or a number.

Examples;

1. Given that x : y = 9 : 4, evaluate







Solution
Step 1

Note; The question above simply means that if x = 9 and y = 4 substitute for x and y in;
















Step 2
Cancellation Process; 4 cancels each other;










Step 3
Cancellation Process; 6 goes in 60 gives 10;

10.






Note; This question simply means that if x =
, substitute for x in
.
Don’t bother yourself about the word “express” it was just used to twist the question and make it more technical.





For further explanation, it means anywhere you see x in 
, you put the whole of 
. Ok, let’s do this!





Step 1






Step 2

NUMERATOR;

Remove the bracket;










Step 3
Find the L.C.M which is 3a – 2;





Step 4
Collect like terms;










Step 5

DENOMINATOR;

Expand by using 2 to multiply all the values in the bracket;













Step 6
Find L.C.M which is 6a – 4;





Step 7
Collect like terms;










Step 8
Combine Numerator and Denominator together;






Step 9
Expand;





Remember the rule which says that when dividing two algebra fractions sign must change to multiplication and the fraction to the right becomes inverse;





Step 10
Note; 6a – 4 and 10a + 2 are two digit values, so we look for their common factors;
NUMERATOR;
6a – 4  ---the common factor will be 2;
2(3a – 2)

Step 11
DENOMINATOR;
10a + 2  ---the common factor will be 2;
2(5a + 1)

Step 12
Combine all of them together;





Step 13
Cancellation Process; 3a – 2 cancels each other and 2 cancels 2;







Step 1
This question similar to example 1 above, so we follow the same process;
This means that x = 3 and y = 4.















Step 2
Cancellation Process; 2 goes in 2 gives 1 while 2 goes in 10 gives 5;










Step 1
Note; This question is similar to example 2 above, so we will follow the same process;
This means that you are to replace x with
;












Step 2

NUMERATOR;

Remove the bracket;










Step 3
Find L.C.M which is 3m + 5;





Step 4
Collect like terms;





Note; 3m – 3m equals 0 and – 5 + 5 also equals o;

 



Note; 0 divided by any value must give 0 as the answer, it’s a rule!;

0

Step 5

DENOMINATOR;

Remove the bracket;










Step 6
Find L.C.M which is 3m + 5;






Step 7
Collect like terms;










Step 8
Combine Numerator and Denominator together;





Step 9
Expand;





Step 10
Change sign to multiplication;





Note; 0 multiplied by any value must give 0 as the answer;

0.






Step 1
Simply put, replace P with 9 and q with 5 in
.






















Step 2
Cancellation Process; 125 goes in 125 to give 1;

1

9 comments:

  1. Example 2 step 5 is wrong. Pls look it up again
    Thanks

    ReplyDelete
    Replies
    1. Yes pls i solve it but the answers are not the same,so that means something is wrong. Pls check
      Thanks

      Delete
  2. Example 2 step five is very wrong
    2[(1+2)/(2+2)]=3/2
    Hence the 2 only affects the numerator
    You're suppose to have (4a+6)/(3a-2)+1
    But then going by your method
    2[(1+2)/(2+2)]
    [(2+4)/(4+4)]
    6/8=3/4
    How come we arrive at different answers if your working is correct.
    For the sake of the Learners make amends.
    Thanks

    ReplyDelete
  3. Yes you have a ponit.you are correct.

    ReplyDelete
  4. Give me more questions please 🙏. I mean now.

    ReplyDelete
  5. Please can someone solve this algebraic fraction;
    If p=2a/1-a² and q=2a/1+a, write 2p-q in terms of a.

    ReplyDelete